What is the integral of u^2cos(u) ?

The integral of u^2cos(u) is u^2sin(u)-2(-ucos(u)+sin(u))+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of u^2cos(u)

\int u^{2} cos (u) d u

u^{2} sin (u) - 2 (- u cos (u) + sin (u)) + C

Solution steps

\int u^{2} cos (u) d u

Apply Integration By Parts

: u^{2} sin (u) - \int 2 u sin (u) d u

= u^{2} sin (u) - \int 2 u sin (u) d u

\int 2 u sin (u) d u = 2 (- u cos (u) + sin (u))

= u^{2} sin (u) - 2 (- u cos (u) + sin (u))

Add a constant to the solution

= u^{2} sin (u) - 2 (- u cos (u) + sin (u)) + C

\frac{d}{d x} (\frac{x ^{2}}{2 + x})

\int x^{4} ln (9 x) d x

y^{^{''}} + 4 y^{^{'}} - 3 y = x

\frac{d}{d x} (sin^{2} (x) + cos^{2} (x))

\int e^{- \frac{t}{2}} d t

What is the integral of u^2cos(u) ?
The integral of u^2cos(u) is u^2sin(u)-2(-ucos(u)+sin(u))+C