What is the derivative of 8xe^x-8e^x ?

The derivative of 8xe^x-8e^x is 8e^xx

What is the first derivative of 8xe^x-8e^x ?

The first derivative of 8xe^x-8e^x is 8e^xx

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\frac{d}{d x} (8 x e^{x} - 8 e^{x})

8 e^{x} x

Solution steps

\frac{d}{d x} (8 x e^{x} - 8 e^{x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (8 x e^{x}) - \frac{d}{d x} (8 e^{x})

\frac{d}{d x} (8 x e^{x}) = 8 (e^{x} + e^{x} x)

\frac{d}{d x} (8 e^{x}) = 8 e^{x}

= 8 (e^{x} + e^{x} x) - 8 e^{x}

Simplify

8 (e^{x} + e^{x} x) - 8 e^{x} : 8 e^{x} x

= 8 e^{x} x

y = 4 x - 3 x^{2}, (2, - 4)

n = 0 \sum \infty \frac{n ^{4}}{4 ^{n}}

f (x) = 2 x + 5

\frac{\partial}{\partial x} (e^{- y} (x^{2} - y^{2}))

\frac{\partial}{\partial x} (e^{(x - 1)^{2}} cos (y))

What is the derivative of 8xe^x-8e^x ?
The derivative of 8xe^x-8e^x is 8e^xx
What is the first derivative of 8xe^x-8e^x ?
The first derivative of 8xe^x-8e^x is 8e^xx