What is the derivative of 9tan(7x) ?

The derivative of 9tan(7x) is 63sec^2(7x)

What is the first derivative of 9tan(7x) ?

The first derivative of 9tan(7x) is 63sec^2(7x)

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\frac{d}{d x} (9 tan (7 x))

63 sec^{2} (7 x)

Solution steps

\frac{d}{d x} (9 tan (7 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 9 \frac{d}{d x} (tan (7 x))

Apply the chain rule:

sec^{2} (7 x) \frac{d}{d x} (7 x)

= sec^{2} (7 x) \frac{d}{d x} (7 x)

\frac{d}{d x} (7 x) = 7

= 9 sec^{2} (7 x) \cdot 7

Simplify

= 63 sec^{2} (7 x)

\frac{4 e ^{(- s)}}{( s ^{2} + 4 s + 13 )}

\int \frac{1}{x ^{2} - 6 x - 13} d x

y^{^{'}} = 0.0017 y (1500 - y)

\int \frac{sin ( 3 x )}{cos ( 3 x )} d x

\frac{s}{s + 2}

What is the derivative of 9tan(7x) ?
The derivative of 9tan(7x) is 63sec^2(7x)
What is the first derivative of 9tan(7x) ?
The first derivative of 9tan(7x) is 63sec^2(7x)