What is the derivative of 2ln(3-x) ?

The derivative of 2ln(3-x) is -2/(3-x)

What is the first derivative of 2ln(3-x) ?

The first derivative of 2ln(3-x) is -2/(3-x)

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\frac{d}{d x} (2 ln (3 - x))

- \frac{2}{3 - x}

Solution steps

\frac{d}{d x} (2 ln (3 - x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (ln (3 - x))

Apply the chain rule:

\frac{1}{3 - x} \frac{d}{d x} (3 - x)

= \frac{1}{3 - x} \frac{d}{d x} (3 - x)

\frac{d}{d x} (3 - x) = - 1

= 2 \cdot \frac{1}{3 - x} (- 1)

Simplify

2 \cdot \frac{1}{3 - x} (- 1) : - \frac{2}{3 - x}

= - \frac{2}{3 - x}

\frac{d}{d x} (x^{1})

\int_{- 1}^{4} ∣ x ∣ d x

\frac{2 s + 6}{8 s ^{2} - 2 s - 3}

y = 2 x^{2}, y^{2} = \frac{1}{2} x

y^{^{'}} y^{- 2} + x y^{- 1} = x

What is the derivative of 2ln(3-x) ?
The derivative of 2ln(3-x) is -2/(3-x)
What is the first derivative of 2ln(3-x) ?
The first derivative of 2ln(3-x) is -2/(3-x)