What is the solution for y^'=(x^2+y^2)/(x*y) ?

The solution for y^'=(x^2+y^2)/(x*y) is y=xsqrt(2ln(x)+c_{1)},y=-xsqrt(2ln(x)+c_{1)}

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y^'=(x^2+y^2)/(x*y)

y^{^{'}} = \frac{x ^{2} + y ^{2}}{x \cdot y}

y = x 2 ln (x) + c_{1}, y = - x 2 ln (x) + c_{1}

Solution steps

y^{'} (x) = \frac{x ^{2} + y ^{2}}{x \cdot y}

Solve Bernoulli ODE:

y = x 2 ln (x) + c_{1}, y = - x 2 ln (x) + c_{1}

y = x 2 ln (x) + c_{1}, y = - x 2 ln (x) + c_{1}

\frac{d}{d x} (cos (10 x))

x y^{^{'}} + y^{^{'}} - (x + 1) cos (x) + y = 0

\frac{d}{d x} ((e^{- x} + e^{x})^{3})

\int \frac{x}{( x - 3 )} d x

\frac{s ^{2} - 1}{( s ^{2} + 1 ) ^{2}}

What is the solution for y^'=(x^2+y^2)/(x*y) ?
The solution for y^'=(x^2+y^2)/(x*y) is y=xsqrt(2ln(x)+c_{1)},y=-xsqrt(2ln(x)+c_{1)}