What is (\partial)/(\partial x)(6y^2-x^2+3) ?

The answer to (\partial)/(\partial x)(6y^2-x^2+3) is -2x

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial x)(6y^2-x^2+3)

\frac{\partial}{\partial x} (6 y^{2} - x^{2} + 3)

- 2 x

Solution steps

\frac{\partial}{\partial x} (6 y^{2} - x^{2} + 3)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (6 y^{2}) - \frac{\partial}{\partial x} (x^{2}) + \frac{\partial}{\partial x} (3)

\frac{\partial}{\partial x} (6 y^{2}) = 0

\frac{\partial}{\partial x} (x^{2}) = 2 x

\frac{\partial}{\partial x} (3) = 0

= 0 - 2 x + 0

Simplify

= - 2 x

\int_{0}^{5} π (25 x^{2} - x^{4}) d x

\int \frac{6 + u}{u} d u

\frac{d}{d y} (\frac{y}{x ^{2} + y ^{2}})

\int x^{2} - 2 x - 8 d x

\int_{3}^{10} (100 - y^{2}) (y + 2) d y

What is (\partial)/(\partial x)(6y^2-x^2+3) ?
The answer to (\partial)/(\partial x)(6y^2-x^2+3) is -2x