What is area-4x^2+6.25x+8,2.5x+7 ?

The answer to area-4x^2+6.25x+8,2.5x+7 is 1.71698…

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area-4x^2+6.25x+8,2.5x+7

area

- 4 x^{2} + 6.25 x + 8, 2.5 x + 7

1.71698 \dots

Solution steps

Apply the area formula:

\int_{- \frac{- 15 + 481}{32}}^{\frac{15 + 481}{32}} - 4 x^{2} + 6.25 x + 8 - (2.5 x + 7) d x

Solve

\int_{- \frac{- 15 + 481}{32}}^{\frac{15 + 481}{32}} - 4 x^{2} + 6.25 x + 8 - (2.5 x + 7) d x : 1.71698 \dots

The area is:

= 1.71698 \dots

\int (sec (x) - 2 x tan (x) - 2 x) d x

\frac{d}{d x} (- 2 ln (\frac{3}{2} x))

7 y^{^{'}} + 5 y = 2 e^{3 x}

f (x) = \frac{e ^{x}}{x ^{2} + 9}

\frac{d}{d t} (t^{3 t})

What is area-4x^2+6.25x+8,2.5x+7 ?
The answer to area-4x^2+6.25x+8,2.5x+7 is 1.71698…