What is the derivative of (x^2+1)^2 ?

The derivative of (x^2+1)^2 is 4x(x^2+1)

What is the first derivative of (x^2+1)^2 ?

The first derivative of (x^2+1)^2 is 4x(x^2+1)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

(x^{2} + 1)^{2}

4 x (x^{2} + 1)

Solution steps

\frac{d}{d x} ((x^{2} + 1)^{2})

Apply the chain rule:

2 (x^{2} + 1) \frac{d}{d x} (x^{2} + 1)

= 2 (x^{2} + 1) \frac{d}{d x} (x^{2} + 1)

\frac{d}{d x} (x^{2} + 1) = 2 x

= 2 (x^{2} + 1) \cdot 2 x

Simplify

= 4 x (x^{2} + 1)

\frac{d}{d x} (\frac{3}{2 x})

f (x) = 8

\frac{( s + 1 )}{s ^{2} + s - 1}

\int_{3}^{7} \frac{t}{7 + t ^{2}} d t

\int \frac{3 - x}{2 x ^{2} + x - 1} d x

What is the derivative of (x^2+1)^2 ?
The derivative of (x^2+1)^2 is 4x(x^2+1)
What is the first derivative of (x^2+1)^2 ?
The first derivative of (x^2+1)^2 is 4x(x^2+1)