What is the tangent of f(x)=sqrt(2x+77),\at x=2 ?

The tangent of f(x)=sqrt(2x+77),\at x=2 is y= 1/9 x+79/9

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of f(x)=sqrt(2x+77),\at x=2

tangent of

f (x) = 2 x + 77, at x = 2

y = \frac{1}{9} x + \frac{79}{9}

Solution steps

Find the tangent point:

(2, 9)

Find the slope of

f (x) = 2 x + 77 : \frac{df ( x )}{d x} = \frac{1}{2 x + 77}

Compute the slope of

f (x) = 2 x + 77

x = 2 : m = \frac{1}{9}

Find the line with slope m=

\frac{1}{9}

and passing through

(2, 9) : y = \frac{1}{9} x + \frac{79}{9}

y = \frac{1}{9} x + \frac{79}{9}

x \to 0 - lim (\frac{( 6 x )}{x ^{4}})

y^{^{''}} - 8 y^{^{'}} + 7 y = 0

\int_{0}^{5} (140 x^{2} + 9800) d x

y = a cos (t) + t^{2} sin (t)

\frac{\partial}{\partial x} ((x + y) e^{x + y})

What is the tangent of f(x)=sqrt(2x+77),\at x=2 ?
The tangent of f(x)=sqrt(2x+77),\at x=2 is y= 1/9 x+79/9