What is the solution for y^{'''}-11y^{''}+24y^'=14e^x ?

The solution for y^{'''}-11y^{''}+24y^'=14e^x is y=c_{1}+c_{2}e^{3x}+c_{3}e^{8x}+e^x

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y^{'''}-11y^{''}+24y^'=14e^x

y^{^{'''}} - 11 y^{^{''}} + 24 y^{^{'}} = 14 e^{x}

y = c_{1} + c_{2} e^{3 x} + c_{3} e^{8 x} + e^{x}

Solution steps

y^{'''} (x) - 11 y^{''} (x) + 24 y^{'} (x) = 14 e^{x}

Solve linear ODE:

y = c_{1} + c_{2} e^{3 x} + c_{3} e^{8 x} + e^{x}

y = c_{1} + c_{2} e^{3 x} + c_{3} e^{8 x} + e^{x}

x \to 1 - lim (ln (1 - x))

\frac{d}{d x} (\frac{1}{( 1 + 2 x ) ^{2}})

\frac{\partial}{\partial z} (4 x y^{3} (z^{2} + 1)^{3})

y = e^{x + 4} + 6

\int e^{iπ z} d z

What is the solution for y^{'''}-11y^{''}+24y^'=14e^x ?
The solution for y^{'''}-11y^{''}+24y^'=14e^x is y=c_{1}+c_{2}e^{3x}+c_{3}e^{8x}+e^x