What is the integral from 1 to infinity of e^{-4x} ?

The integral from 1 to infinity of e^{-4x} is 1/(4e^4)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 1 to infinity of e^{-4x}

\int_{1}^{\infty} e^{- 4 x} d x

\frac{1}{4 e ^{4}}

Decimal Notation

0.00457 \dots

Solution steps

\int_{1}^{\infty} e^{- 4 x} d x

Compute the indefinite integral:

\int e^{- 4 x} d x = - \frac{1}{4} e^{- 4 x} + C

Compute the boundaries:

\int_{1}^{\infty} e^{- 4 x} d x = 0 - (- \frac{1}{4 e ^{4}})

= 0 - (- \frac{1}{4 e ^{4}})

Simplify

= \frac{1}{4 e ^{4}}

\int \frac{sec ( x ) tan ( x )}{sec ( x ) - 2} d x

\frac{d y}{d t} - 5 y = - 9 e^{2 t}

\frac{2 x ^{3}}{3} + \frac{x ^{2}}{2} + 6 x + 6

x \to 2 lim (ln (x))

\int \frac{1}{x ^{2} 16 - x} d x

What is the integral from 1 to infinity of e^{-4x} ?
The integral from 1 to infinity of e^{-4x} is 1/(4e^4)