What is area sec^2(x),8cos(x),-pi/3 , pi/3 ?

The answer to area sec^2(x),8cos(x),-pi/3 , pi/3 is 6sqrt(3)

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area sec^2(x),8cos(x),-pi/3 , pi/3

area

sec^{2} (x), 8 cos (x), - \frac{π}{3}, \frac{π}{3}

63

Decimal Notation

10.39230 \dots

Solution steps

Apply the area formula:

\int_{- \frac{π}{3}}^{\frac{π}{3}} sec^{2} (x) - 8 cos (x) d x

Solve

\int_{- \frac{π}{3}}^{\frac{π}{3}} sec^{2} (x) - 8 cos (x) d x : 63

The area is:

= 63

\frac{\partial}{\partial x} ((3 z + 2)^{5} e^{(- x - 5)} ln (4 y - 1))

\frac{1 - lo g _{e} ( x )}{x ^{2}}

\int sec^{2} (θ) d θ

f (x) = 7 x^{4} + 4 x^{2} x 3 + 1

\int (1 + x) d x

What is area sec^2(x),8cos(x),-pi/3 , pi/3 ?
The answer to area sec^2(x),8cos(x),-pi/3 , pi/3 is 6sqrt(3)