What is (\partial)/(\partial x)(1+y) ?

The answer to (\partial)/(\partial x)(1+y) is 0

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(\partial)/(\partial x)(1+y)

\frac{\partial}{\partial x} (1 + y)

0

Solution steps

\frac{\partial}{\partial x} (1 + y)

Treat

y

as a constant

Derivative of a constant:

\frac{d}{d x} (a) = 0

= 0

\frac{d}{d x} ((arcsin (1 - x^{2}))^{4})

\int_{1}^{2} 2 x^{4} ln (x) d x

\int y x e^{x y} d y

e^{- 2 x}, 0

\frac{d}{d x} (x + x^{2} - 1)

What is (\partial)/(\partial x)(1+y) ?
The answer to (\partial)/(\partial x)(1+y) is 0