What is (\partial)/(\partial x)(2x^2y-3) ?

The answer to (\partial)/(\partial x)(2x^2y-3) is 4xy

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial x)(2x^2y-3)

\frac{\partial}{\partial x} (2 x^{2} y - 3)

4 x y

Solution steps

\frac{\partial}{\partial x} (2 x^{2} y - 3)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (2 x^{2} y) - \frac{\partial}{\partial x} (3)

\frac{\partial}{\partial x} (2 x^{2} y) = 4 y x

\frac{\partial}{\partial x} (3) = 0

= 4 y x - 0

Simplify

= 4 x y

\int x^{2} lo g_{10} (x) d x

f (x) = \frac{x ^{2} - 3 x + 2}{x ^{2} - 1}

y = 2.8414 x^{2} - 1.2187 x + 0.5399

\frac{d}{d x} ((x^{2} + x + 2)^{\frac{2}{3}})

y = x^{3} + 1

What is (\partial)/(\partial x)(2x^2y-3) ?
The answer to (\partial)/(\partial x)(2x^2y-3) is 4xy