What is the derivative of cos(2x+sin(2pi)) ?

The derivative of cos(2x+sin(2pi)) is -sin(2x)*2

What is the first derivative of cos(2x+sin(2pi)) ?

The first derivative of cos(2x+sin(2pi)) is -sin(2x)*2

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\frac{d}{d x} (cos (2 x) + sin (2 π))

- sin (2 x) \cdot 2

Solution steps

\frac{d}{d x} (cos (2 x) + sin (2 π))

Simplify

cos (2 x) + sin (2 π) : cos (2 x)

= \frac{d}{d x} (cos (2 x))

Apply the chain rule:

- sin (2 x) \frac{d}{d x} (2 x)

= - sin (2 x) \frac{d}{d x} (2 x)

\frac{d}{d x} (2 x) = 2

= - sin (2 x) \cdot 2

\int_{1}^{t} \frac{25}{x ^{3}} d x

\frac{d}{d x} (cos (x + a))

\frac{7}{s ^{5}}

\int \frac{x ^{2}}{( a ^{2} - x ^{2} ) ^{\frac{3}{2}}} d x

x \to 0 lim (x I n x)

What is the derivative of cos(2x+sin(2pi)) ?
The derivative of cos(2x+sin(2pi)) is -sin(2x)*2
What is the first derivative of cos(2x+sin(2pi)) ?
The first derivative of cos(2x+sin(2pi)) is -sin(2x)*2