What is the derivative of tan(sin(x)) ?

The derivative of tan(sin(x)) is sec^2(sin(x))cos(x)

What is the first derivative of tan(sin(x)) ?

The first derivative of tan(sin(x)) is sec^2(sin(x))cos(x)

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\frac{d}{d x} (tan (sin (x)))

sec^{2} (sin (x)) cos (x)

Solution steps

\frac{d}{d x} (tan (sin (x)))

Apply the chain rule:

sec^{2} (sin (x)) \frac{d}{d x} (sin (x))

= sec^{2} (sin (x)) \frac{d}{d x} (sin (x))

\frac{d}{d x} (sin (x)) = cos (x)

= sec^{2} (sin (x)) cos (x)

\int \frac{1}{x ^{2} 3 x ^{2} + 4} d x

y = 1 n (x^{3})

\frac{\partial}{\partial y} (\frac{x}{x ^{2} + y ^{2} + z ^{2}})

y = 2 + ∣ x - 1 ∣, y = - \frac{1}{5} x + 7

\int_{1}^{5 e} \frac{1}{3 x} d x

What is the derivative of tan(sin(x)) ?
The derivative of tan(sin(x)) is sec^2(sin(x))cos(x)
What is the first derivative of tan(sin(x)) ?
The first derivative of tan(sin(x)) is sec^2(sin(x))cos(x)