What is the derivative of y=1n(x^3) ?

The derivative of y=1n(x^3) is 3nx^2

What is the first derivative of y=1n(x^3) ?

The first derivative of y=1n(x^3) is 3nx^2

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derivative of

y = 1 n (x^{3})

3 n x^{2}

Solution steps

\frac{d}{d x} (1 \cdot n x^{3})

Simplify

1 \cdot n x^{3} : n x^{3}

= \frac{d}{d x} (n x^{3})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= n \frac{d}{d x} (x^{3})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= n \cdot 3 x^{3 - 1}

Simplify

= 3 n x^{2}

\frac{\partial}{\partial y} (\frac{x}{x ^{2} + y ^{2} + z ^{2}})

y = 2 + ∣ x - 1 ∣, y = - \frac{1}{5} x + 7

\int_{1}^{5 e} \frac{1}{3 x} d x

\int \frac{5 ln ( x )}{x} d x

\int (2 - 3 x)^{5} d x

What is the derivative of y=1n(x^3) ?
The derivative of y=1n(x^3) is 3nx^2
What is the first derivative of y=1n(x^3) ?
The first derivative of y=1n(x^3) is 3nx^2