What is the tangent of y= 2/x ,(-4,-1/2) ?

The tangent of y= 2/x ,(-4,-1/2) is y=-1/8 x-1

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tangent of y= 2/x ,(-4,-1/2)

tangent of

y = \frac{2}{x}, (- 4, - \frac{1}{2})

y = - \frac{1}{8} x - 1

Solution steps

Find the slope of

y = \frac{2}{x} : \frac{d y}{d x} = - \frac{2}{x ^{2}}

Compute the slope of

y = \frac{2}{x}

(- 4, - \frac{1}{2}) : m = - \frac{1}{8}

Find the line with slope m=

- \frac{1}{8}

and passing through

(- 4, - \frac{1}{2}) : y = - \frac{1}{8} x - 1

y = - \frac{1}{8} x - 1

\int \frac{3 x}{16 - 9 x ^{2}} d x

x \to 0 + lim (x ln (x^{4}))

\frac{\partial}{\partial x} (x ln (\frac{x ^{2}}{y ^{3}}))

\int_{- 2}^{3} \frac{26}{x ^{4}} d x

What is the tangent of y= 2/x ,(-4,-1/2) ?
The tangent of y= 2/x ,(-4,-1/2) is y=-1/8 x-1