What is the solution for x^2y^{''}+9xy^'-20y= 5/(x^3) ?

The solution for x^2y^{''}+9xy^'-20y= 5/(x^3) is y=c_{1}x^2+(c_{2})/(x^{10)}-1/(7x^3)

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x^2y^{''}+9xy^'-20y= 5/(x^3)

x^{2} y^{^{''}} + 9 x y^{^{'}} - 20 y = \frac{5}{x ^{3}}

y = c_{1} x^{2} + \frac{c _{2}}{x ^{10}} - \frac{1}{7 x ^{3}}

Solution steps

x^{2} y^{''} (x) + 9 x y^{'} (x) - 20 y = \frac{5}{x ^{3}}

Solve linear ODE:

y = c_{1} x^{2} + \frac{c _{2}}{x ^{10}} - \frac{1}{7 x ^{3}}

y = c_{1} x^{2} + \frac{c _{2}}{x ^{10}} - \frac{1}{7 x ^{3}}

f (x) = csc (x) (x + cot (x))

x \to 0 lim (\frac{1}{x + 5})

\frac{\partial}{\partial x} ((5 x - y)^{7})

\frac{d}{d x} (4 x^{\frac{5}{4}} + 6 x^{\frac{3}{2}} + 9 x)

\int x^{2} - y d y

What is the solution for x^2y^{''}+9xy^'-20y= 5/(x^3) ?
The solution for x^2y^{''}+9xy^'-20y= 5/(x^3) is y=c_{1}x^2+(c_{2})/(x^{10)}-1/(7x^3)