What is the derivative of 5x^2cos(x-4x) ?

The derivative of 5x^2cos(x-4x) is 5(2xcos(x)-x^2sin(x))-4

What is the first derivative of 5x^2cos(x-4x) ?

The first derivative of 5x^2cos(x-4x) is 5(2xcos(x)-x^2sin(x))-4

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\frac{d}{d x} (5 x^{2} cos (x) - 4 x)

5 (2 x cos (x) - x^{2} sin (x)) - 4

Solution steps

\frac{d}{d x} (5 x^{2} cos (x) - 4 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (5 x^{2} cos (x)) - \frac{d}{d x} (4 x)

\frac{d}{d x} (5 x^{2} cos (x)) = 5 (2 x cos (x) - x^{2} sin (x))

\frac{d}{d x} (4 x) = 4

= 5 (2 x cos (x) - x^{2} sin (x)) - 4

y = \frac{4}{1 + x ^{2}}, y = 1

\frac{d}{d t} (t^{2} - 2 t)

x^{^{'}} = 0.1078 \cdot (1 - \frac{x}{105900}) x - 0.1 \cdot x

(2.6) (5.15)

x \to 1 lim (2 x^{3} - 4 x^{2} + x + 9)

What is the derivative of 5x^2cos(x-4x) ?
The derivative of 5x^2cos(x-4x) is 5(2xcos(x)-x^2sin(x))-4
What is the first derivative of 5x^2cos(x-4x) ?
The first derivative of 5x^2cos(x-4x) is 5(2xcos(x)-x^2sin(x))-4