What is the derivative of 3/(sqrt(2x+1)) ?

The derivative of 3/(sqrt(2x+1)) is -3/((2x+1)^{3/2)}

What is the first derivative of 3/(sqrt(2x+1)) ?

The first derivative of 3/(sqrt(2x+1)) is -3/((2x+1)^{3/2)}

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\frac{d}{d x} (\frac{3}{2 x + 1})

- \frac{3}{( 2 x + 1 ) ^{\frac{3}{2}}}

Solution steps

\frac{d}{d x} (\frac{3}{2 x + 1})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 \frac{d}{d x} (\frac{1}{2 x + 1})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 3 \frac{d}{d x} ((2 x + 1)^{- \frac{1}{2}})

Apply the chain rule:

- \frac{1}{2 ( 2 x + 1 ) ^{\frac{3}{2}}} \frac{d}{d x} (2 x + 1)

= - \frac{1}{2 ( 2 x + 1 ) ^{\frac{3}{2}}} \frac{d}{d x} (2 x + 1)

\frac{d}{d x} (2 x + 1) = 2

= 3 (- \frac{1}{2 ( 2 x + 1 ) ^{\frac{3}{2}}} \cdot 2)

Simplify

3 (- \frac{1}{2 ( 2 x + 1 ) ^{\frac{3}{2}}} \cdot 2) : - \frac{3}{( 2 x + 1 ) ^{\frac{3}{2}}}

= - \frac{3}{( 2 x + 1 ) ^{\frac{3}{2}}}

\frac{d}{d x} (\frac{x ^{2} + 2 x + 1}{x ^{2} - 2 x + 1})

\frac{d}{d x} ((3 x + 5) x^{2})

y^{^{''}} - 6 y^{^{'}} + 8 y = 0

\int sin^{7} (x) cos^{2} (x) d x

y = lo g_{5} (x)

What is the derivative of 3/(sqrt(2x+1)) ?
The derivative of 3/(sqrt(2x+1)) is -3/((2x+1)^{3/2)}
What is the first derivative of 3/(sqrt(2x+1)) ?
The first derivative of 3/(sqrt(2x+1)) is -3/((2x+1)^{3/2)}