What is the limit as x approaches 3 of (3-x)/(x^2-9) ?

The limit as x approaches 3 of (3-x)/(x^2-9) is -1/6

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limit as x approaches 3 of (3-x)/(x^2-9)

x \to 3 lim (\frac{3 - x}{x ^{2} - 9})

- \frac{1}{6}

Decimal Notation

- 0.16666 \dots

Solution steps

x \to 3 lim (\frac{3 - x}{x ^{2} - 9})

Simplify

\frac{3 - x}{x ^{2} - 9} : - \frac{1}{x + 3}

= x \to 3 lim (- \frac{1}{x + 3})

Plug in the value

x = 3

= - \frac{1}{3 + 3}

Simplify

= - \frac{1}{6}

\int \frac{1}{x ^{2} + 4 x + 20} d x

f (t) = t sin (π t)

\int x^{2} tan (x^{3}) d x

\frac{1}{x ^{6}} \frac{d y}{d x} = 25 + 20 y

\frac{( 1 - s ^{- 6} ) ^{2}}{( 1 - s ^{- 1} ) ^{2}}

What is the limit as x approaches 3 of (3-x)/(x^2-9) ?
The limit as x approaches 3 of (3-x)/(x^2-9) is -1/6