What is the derivative of sqrt(x^2+8) ?

The derivative of sqrt(x^2+8) is x/(sqrt(x^2+8))

What is the first derivative of sqrt(x^2+8) ?

The first derivative of sqrt(x^2+8) is x/(sqrt(x^2+8))

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derivative of

x^{2} + 8

\frac{x}{x ^{2} + 8}

Solution steps

\frac{d}{d x} (x^{2} + 8)

Apply the chain rule:

\frac{1}{2 x ^{2} + 8} \frac{d}{d x} (x^{2} + 8)

= \frac{1}{2 x ^{2} + 8} \frac{d}{d x} (x^{2} + 8)

\frac{d}{d x} (x^{2} + 8) = 2 x

= \frac{1}{2 x ^{2} + 8} \cdot 2 x

Simplify

\frac{1}{2 x ^{2} + 8} \cdot 2 x : \frac{x}{x ^{2} + 8}

= \frac{x}{x ^{2} + 8}

f (x) = x^{2} - 10 x + 34 + x^{2} + 16

\int (x - \frac{3}{x})^{2} x d x

\frac{\partial}{\partial x} (x ln (y) + y^{2} ln (x))

\frac{d}{d y} (3 x^{2} y^{2} + \frac{x}{y})

\frac{d}{d x} ((3 x^{4} - 2) (1 + 4 x^{3}))

What is the derivative of sqrt(x^2+8) ?
The derivative of sqrt(x^2+8) is x/(sqrt(x^2+8))
What is the first derivative of sqrt(x^2+8) ?
The first derivative of sqrt(x^2+8) is x/(sqrt(x^2+8))