What is the sum from n=1 to infinity of 1/((2n+3)^3) ?

The sum from n=1 to infinity of 1/((2n+3)^3) is converges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sum from n=1 to infinity of 1/((2n+3)^3)

n = 1 \sum \infty \frac{1}{( 2 n + 3 ) ^{3}}

converges

Solution steps

n = 1 \sum \infty \frac{1}{( 2 n + 3 ) ^{3}}

Apply Series Comparison Test:

converges

= converges

f (x) = 8 (x - \frac{1}{x}), at x = 2

\frac{d}{d x} (f (x)^{2} (x))

\frac{d}{d t} (t^{3} e^{t})

\frac{d}{d x} ((ln (x) - 1)^{2})

\frac{d}{d x} (e^{3 - 5 x})

What is the sum from n=1 to infinity of 1/((2n+3)^3) ?
The sum from n=1 to infinity of 1/((2n+3)^3) is converges