What is the (cos(pi/x))^' ?

The (cos(pi/x))^' is (pisin(pi/x))/(x^2)

What is the first (cos(pi/x))^' ?

The first (cos(pi/x))^' is (pisin(pi/x))/(x^2)

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(cos (\frac{π}{x}))^{^{'}}

\frac{π sin ( \frac{π}{x} )}{x ^{2}}

Solution steps

(cos (\frac{π}{x}))^{'}

Apply the chain rule:

- sin (\frac{π}{x}) (\frac{π}{x})^{'}

= - sin (\frac{π}{x}) (\frac{π}{x})^{'}

(\frac{π}{x})^{'} = - \frac{π}{x ^{2}}

= - sin (\frac{π}{x}) (- \frac{π}{x ^{2}})

Simplify

- sin (\frac{π}{x}) (- \frac{π}{x ^{2}}) : \frac{π sin ( \frac{π}{x} )}{x ^{2}}

= \frac{π sin ( \frac{π}{x} )}{x ^{2}}

y^{^{''}} + 5 y^{^{'}} + 4 y = - 8 t e^{2 t}

\int_{0}^{2} \frac{x}{x ^{2} + 4 x + 8} d x

\int 4 e^{- t} d t

y = e^{6 e^{x}}

\frac{d}{d x} (- 5 x^{- 2})

What is the (cos(pi/x))^' ?
The (cos(pi/x))^' is (pisin(pi/x))/(x^2)
What is the first (cos(pi/x))^' ?
The first (cos(pi/x))^' is (pisin(pi/x))/(x^2)