What is the integral of sin(3x-7) ?

The integral of sin(3x-7) is -1/3 cos(3x-7)+C

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integral of sin(3x-7)

\int sin (3 x - 7) d x

- \frac{1}{3} cos (3 x - 7) + C

Solution steps

\int sin (3 x - 7) d x

Apply u-substitution

: \int sin (u) \frac{1}{3} d u

= \int sin (u) \frac{1}{3} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{3} \cdot \int sin (u) d u

Use the common integral:

\int sin (u) d u = - cos (u)

= \frac{1}{3} (- cos (u))

Substitute back

u = 3 x - 7

= \frac{1}{3} (- cos (3 x - 7))

Simplify

= - \frac{1}{3} cos (3 x - 7)

Add a constant to the solution

= - \frac{1}{3} cos (3 x - 7) + C

\frac{d}{d t} (9 cos (t))

\int 8 sec^{4} (x) d x

\int 1 + sin (θ) d θ

f (x) = sin (x) - cos (x)

y = - 2 x^{2} + 32 x - 7

What is the integral of sin(3x-7) ?
The integral of sin(3x-7) is -1/3 cos(3x-7)+C