What is the derivative of 1/(x^2-3x^2) ?

The derivative of 1/(x^2-3x^2) is -2/(x^3)-6x

What is the first derivative of 1/(x^2-3x^2) ?

The first derivative of 1/(x^2-3x^2) is -2/(x^3)-6x

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\frac{d}{d x} (\frac{1}{x ^{2}} - 3 x^{2})

- \frac{2}{x ^{3}} - 6 x

Solution steps

\frac{d}{d x} (\frac{1}{x ^{2}} - 3 x^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{1}{x ^{2}}) - \frac{d}{d x} (3 x^{2})

\frac{d}{d x} (\frac{1}{x ^{2}}) = - \frac{2}{x ^{3}}

\frac{d}{d x} (3 x^{2}) = 6 x

= - \frac{2}{x ^{3}} - 6 x

\int (2 + y^{2})^{2} d y

\frac{( 6 x ^{9} + x ^{8} )}{2 x ^{4}}

\frac{\partial}{\partial x} (y + 2 x)

\int_{1}^{3} 3 x^{- \frac{3}{2}} d x

\int (5 x^{4} + 12 x^{3} + 6 x - 2) d x

What is the derivative of 1/(x^2-3x^2) ?
The derivative of 1/(x^2-3x^2) is -2/(x^3)-6x
What is the first derivative of 1/(x^2-3x^2) ?
The first derivative of 1/(x^2-3x^2) is -2/(x^3)-6x