What is the tangent of f(x)=-2sin(x),\at x= pi/4 ?

The tangent of f(x)=-2sin(x),\at x= pi/4 is y=-sqrt(2)x-sqrt(2)+pi/(2sqrt(2))

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tangent of f(x)=-2sin(x),\at x= pi/4

tangent of

f (x) = - 2 sin (x), at x = \frac{π}{4}

y = - 2 x - 2 + \frac{π}{2 2}

Solution steps

Find the tangent point:

(\frac{π}{4}, - 2)

Find the slope of

f (x) = - 2 sin (x) : \frac{df ( x )}{d x} = - 2 cos (x)

Compute the slope of

f (x) = - 2 sin (x)

x = \frac{π}{4} : m = - 2

Find the line with slope m=

- 2

and passing through

(\frac{π}{4}, - 2) : y = - 2 x - 2 + \frac{π}{2 2}

y = - 2 x - 2 + \frac{π}{2 2}

\int \frac{y ^{3}}{y ^{2} + 4} d y

f (x) = 4 tan (x), at x = \frac{π}{4}

\int_{- 2}^{3} \frac{43}{x ^{4}} d x

- 5 x^{3}

y^{^{''}} - 4 y^{^{'}} - 12 y = sin (2 t) + t e^{4 t}

What is the tangent of f(x)=-2sin(x),\at x= pi/4 ?
The tangent of f(x)=-2sin(x),\at x= pi/4 is y=-sqrt(2)x-sqrt(2)+pi/(2sqrt(2))