What is the sum from n=1 to infinity}((-1)^{n-1 of)/(nsqrt(n)) ?

The sum from n=1 to infinity}((-1)^{n-1 of)/(nsqrt(n)) is converges

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sum from n=1 to infinity}((-1)^{n-1 of)/(nsqrt(n))

n = 1 \sum \infty \frac{( - 1 ) ^{n - 1}}{n n}

converges

Solution steps

n = 1 \sum \infty \frac{( - 1 ) ^{n - 1}}{n n}

Apply Alternating Series Test:

converges

= converges

\frac{d ^{2}}{d x ^{2}} (\frac{x}{x - 4})

sin (x) tan (2 x) + cos (x), 0

n = 2 \sum \infty (- 1)^{n} \frac{n + 1}{2 n - 3}

x = y, 4 x + y^{2} = 12

\frac{d y}{d x} + \frac{y}{x} = \frac{1}{y ^{2} x}

What is the sum from n=1 to infinity}((-1)^{n-1 of)/(nsqrt(n)) ?
The sum from n=1 to infinity}((-1)^{n-1 of)/(nsqrt(n)) is converges