What is the limit as x approaches 0 of log_{e}(1+x) ?

The limit as x approaches 0 of log_{e}(1+x) is 0

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limit as x approaches 0 of log_{e}(1+x)

x \to 0 lim (lo g_{e} (1 + x))

0

Solution steps

x \to 0 lim (lo g_{e} (1 + x))

Plug in the value

x = 0

= lo g_{e} (1 + 0)

Simplify

lo g_{e} (1 + 0) : 0

= 0

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What is the limit as x approaches 0 of log_{e}(1+x) ?
The limit as x approaches 0 of log_{e}(1+x) is 0