What is the derivative of 4-3x^2 ?

The derivative of 4-3x^2 is -6x

What is the first derivative of 4-3x^2 ?

The first derivative of 4-3x^2 is -6x

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\frac{d}{d x} (4 - 3 x^{2})

- 6 x

Solution steps

\frac{d}{d x} (4 - 3 x^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (4) - \frac{d}{d x} (3 x^{2})

\frac{d}{d x} (4) = 0

\frac{d}{d x} (3 x^{2}) = 6 x

= 0 - 6 x

Simplify

= - 6 x

4 x^{\frac{5}{4}} + 2 x^{\frac{3}{2}} + 4 x

\int \frac{4 x ^{2} - 1}{( x ^{2} + 4 ) ( 2 - x )} d x

f (x) = - \frac{x}{4}

f (x) = 4 x^{2} - 4 x + 1, at x = 1, y = 0

\int cos (4 x) sin (x) d x