What is the derivative of 5cos(4x) ?

The derivative of 5cos(4x) is -20sin(4x)

What is the first derivative of 5cos(4x) ?

The first derivative of 5cos(4x) is -20sin(4x)

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\frac{d}{d x} (5 cos (4 x))

- 20 sin (4 x)

Solution steps

\frac{d}{d x} (5 cos (4 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 5 \frac{d}{d x} (cos (4 x))

Apply the chain rule:

- sin (4 x) \frac{d}{d x} (4 x)

= - sin (4 x) \frac{d}{d x} (4 x)

\frac{d}{d x} (4 x) = 4

= 5 (- sin (4 x) \cdot 4)

Simplify

= - 20 sin (4 x)

\int \frac{3 x + 5}{x ^{2} + x + 1} d x

\int \frac{t}{1 - t ^{4}} d t

h = (x x^{2} + 2), (x + h, (x + h)^{2} + 2)

\int \frac{2 x}{x ^{2} - 27} d x

\int \frac{3}{2} x d x

What is the derivative of 5cos(4x) ?
The derivative of 5cos(4x) is -20sin(4x)
What is the first derivative of 5cos(4x) ?
The first derivative of 5cos(4x) is -20sin(4x)