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Popular >

y^'=ysin(4x)

Solution

y^{^{'}} = y sin (4 x)

Solution

y = e^{- \frac{1}{4} c o s (4 x) + c_{1}}

Solution steps

y^{'} (x) = y sin (4 x)

Solve separable ODE:

y = e^{- \frac{1}{4} c o s (4 x) + c_{1}}

y = e^{- \frac{1}{4} c o s (4 x) + c_{1}}

Popular Examples

d/(dy)(2xsin(y))

\frac{d}{d y} (2 x sin (y))

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integral of 1/(sqrt(x))

\int \frac{1}{x} d x

integral of 1/(81+16x^2)

\int \frac{1}{81 + 16 x ^{2}} d x

y^{^{'}} + y = sin (2 t)

Frequently Asked Questions (FAQ)

What is the solution for y^'=ysin(4x) ?
The solution for y^'=ysin(4x) is y=e^{-1/4 cos(4x)+c_{1}}