What is the derivative of e^{{r}(xx}) ?

The derivative of e^{{r}(xx}) is e^{{r}(x)x}(x derivative of {r}(x)+{r}(x))

What is the first derivative of e^{{r}(xx}) ?

The first derivative of e^{{r}(xx}) is e^{{r}(x)x}(x derivative of {r}(x)+{r}(x))

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\frac{d}{d x} (e^{r (x) x})

e^{r (x) x} (x \frac{d}{d x} (r (x)) + r (x))

Solution steps

\frac{d}{d x} (e^{r (x) x})

Apply the chain rule:

e^{r (x) x} \frac{d}{d x} (r (x) x)

= e^{r (x) x} \frac{d}{d x} (r (x) x)

\frac{d}{d x} (r (x) x) = x \frac{d}{d x} (r (x)) + r (x)

= e^{r (x) x} (x \frac{d}{d x} (r (x)) + r (x))

\frac{d}{d y} (sin (x) cos (y))

f (x) = e^{- x^{2}}, at x = 5

x \to 0 lim (- \frac{3}{1 - 3 x})

f (x) = cot^{2} (sin (θ))

\frac{d}{d x} (sec (x) y)

What is the derivative of e^{{r}(xx}) ?
The derivative of e^{{r}(xx}) is e^{{r}(x)x}(x derivative of {r}(x)+{r}(x))
What is the first derivative of e^{{r}(xx}) ?
The first derivative of e^{{r}(xx}) is e^{{r}(x)x}(x derivative of {r}(x)+{r}(x))