What is the tangent of f(x)=-3x^2-4x-2,\at x=2 ?

The tangent of f(x)=-3x^2-4x-2,\at x=2 is y=-16x+10

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tangent of f(x)=-3x^2-4x-2,\at x=2

tangent of

f (x) = - 3 x^{2} - 4 x - 2, at x = 2

y = - 16 x + 10

Solution steps

Find the tangent point:

(2, - 22)

Find the slope of

f (x) = - 3 x^{2} - 4 x - 2 : \frac{df ( x )}{d x} = - 6 x - 4

Compute the slope of

f (x) = - 3 x^{2} - 4 x - 2

x = 2 : m = - 16

Find the line with slope m=

- 16

and passing through

(2, - 22) : y = - 16 x + 10

y = - 16 x + 10

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What is the tangent of f(x)=-3x^2-4x-2,\at x=2 ?
The tangent of f(x)=-3x^2-4x-2,\at x=2 is y=-16x+10