What is the limit as x approaches (3pi)/2 of ln(1+sin(x)) ?

The limit as x approaches (3pi)/2 of ln(1+sin(x)) is -infinity

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limit as x approaches (3pi)/2 of ln(1+sin(x))

x \to \frac{3 π}{2} lim (ln (1 + sin (x)))

- \infty

Solution steps

x \to \frac{3 π}{2} lim (ln (1 + sin (x)))

Apply the Limit Chain Rule:

- \infty

= - \infty

\frac{d}{d y} (2 x + 3 y)

\int_{4}^{8} \frac{x}{x ^{2} - 1} d x

\frac{d}{d x} (3 x e^{x})

y = e^{8 x} cos (11 x)

f (x) = 5 (1 - x^{2})^{9}

What is the limit as x approaches (3pi)/2 of ln(1+sin(x)) ?
The limit as x approaches (3pi)/2 of ln(1+sin(x)) is -infinity