What is the derivative of tan(x^2-4x) ?

The derivative of tan(x^2-4x) is sec^2(x^2-4x)(2x-4)

What is the first derivative of tan(x^2-4x) ?

The first derivative of tan(x^2-4x) is sec^2(x^2-4x)(2x-4)

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\frac{d}{d x} (tan (x^{2} - 4 x))

sec^{2} (x^{2} - 4 x) (2 x - 4)

Solution steps

\frac{d}{d x} (tan (x^{2} - 4 x))

Apply the chain rule:

sec^{2} (x^{2} - 4 x) \frac{d}{d x} (x^{2} - 4 x)

= sec^{2} (x^{2} - 4 x) \frac{d}{d x} (x^{2} - 4 x)

\frac{d}{d x} (x^{2} - 4 x) = 2 x - 4

= sec^{2} (x^{2} - 4 x) (2 x - 4)

x \to - \infty lim (x^{3} - 5 x^{2})

\int x^{2} \cdot x - 5 d x

y = x^{2} (x^{3} - 1)^{5}

y = 2 x + 1, at x = 4

(x - y - 1)^{3} = x

What is the derivative of tan(x^2-4x) ?
The derivative of tan(x^2-4x) is sec^2(x^2-4x)(2x-4)
What is the first derivative of tan(x^2-4x) ?
The first derivative of tan(x^2-4x) is sec^2(x^2-4x)(2x-4)