What is the sum from n=1 to infinity of cos(4n) ?

The sum from n=1 to infinity of cos(4n) is diverges

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sum from n=1 to infinity of cos(4n)

n = 1 \sum \infty cos (4 n)

diverges

Solution steps

n = 1 \sum \infty cos (4 n)

Apply Series Divergence Test:

diverges

= diverges

\frac{d}{d x} (a e^{a x})

\frac{d}{d x} ((x^{3} + 2 x - 7) (3 + x - x^{2}))

\frac{d}{d x} ((x + \frac{1}{x})^{- 1})

\frac{d y}{d x} - 2 x y = 8 x

x \to 1 - lim (∣ x - 1 ∣)

What is the sum from n=1 to infinity of cos(4n) ?
The sum from n=1 to infinity of cos(4n) is diverges