What is the derivative of f(x)=x^2-9 ?

The derivative of f(x)=x^2-9 is 2x

What is the first derivative of f(x)=x^2-9 ?

The first derivative of f(x)=x^2-9 is 2x

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derivative of

f (x) = x^{2} - 9

2 x

Solution steps

\frac{d}{d x} (x^{2} - 9)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) - \frac{d}{d x} (9)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (9) = 0

= 2 x - 0

Simplify

= 2 x

\int x^{2} (x^{3} + 2)^{2} d x

\frac{s + 1}{s ( s ^{2} + s + 1 )}

t \to 8 - lim (\frac{t ^{8}}{t - 8})

\int - \frac{2200 x}{25 - x ^{2}} d x

x \to 0 lim (x ln (x^{3}))

What is the derivative of f(x)=x^2-9 ?
The derivative of f(x)=x^2-9 is 2x
What is the first derivative of f(x)=x^2-9 ?
The first derivative of f(x)=x^2-9 is 2x