What is the derivative of f(x)=x^2-sec(x) ?

The derivative of f(x)=x^2-sec(x) is 2x-sec(x)tan(x)

What is the first derivative of f(x)=x^2-sec(x) ?

The first derivative of f(x)=x^2-sec(x) is 2x-sec(x)tan(x)

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derivative of

f (x) = x^{2} - sec (x)

2 x - sec (x) tan (x)

Solution steps

\frac{d}{d x} (x^{2} - sec (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) - \frac{d}{d x} (sec (x))

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (sec (x)) = sec (x) tan (x)

= 2 x - sec (x) tan (x)

x y^{^{''}} = y^{^{'}}

s (t) = \frac{400 t}{( t ^{2 + 5} ) ^{3}}

x \to 4 lim (15)

\frac{d y}{d x} = \frac{( x + y )}{6}

\frac{\partial}{\partial x} (yz)

What is the derivative of f(x)=x^2-sec(x) ?
The derivative of f(x)=x^2-sec(x) is 2x-sec(x)tan(x)
What is the first derivative of f(x)=x^2-sec(x) ?
The first derivative of f(x)=x^2-sec(x) is 2x-sec(x)tan(x)