What is the derivative of (x^3/(1-x)) ?

The derivative of (x^3/(1-x)) is (3x^2-2x^3)/((1-x)^2)

What is the first derivative of (x^3/(1-x)) ?

The first derivative of (x^3/(1-x)) is (3x^2-2x^3)/((1-x)^2)

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\frac{d}{d x} (\frac{x ^{3}}{1 - x})

\frac{3 x ^{2} - 2 x ^{3}}{( 1 - x ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{x ^{3}}{1 - x})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( x ^{3} ) ( 1 - x ) - \frac{d}{d x} ( 1 - x ) x ^{3}}{( 1 - x ) ^{2}}

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (1 - x) = - 1

= \frac{3 x ^{2} ( 1 - x ) - ( - 1 ) x ^{3}}{( 1 - x ) ^{2}}

Simplify

\frac{3 x ^{2} ( 1 - x ) - ( - 1 ) x ^{3}}{( 1 - x ) ^{2}} : \frac{3 x ^{2} - 2 x ^{3}}{( 1 - x ) ^{2}}

= \frac{3 x ^{2} - 2 x ^{3}}{( 1 - x ) ^{2}}

f (x) = x^{2} + 2, - 3, 1

\frac{d y}{d x}, y = e^{9 x^{5}}

arccsc (x)

\int \frac{x ^{3} + 2 x - 6}{x ^{3}} d x

\frac{d}{d x} (\frac{1}{4 x ^{\frac{3}{2}}})

What is the derivative of (x^3/(1-x)) ?
The derivative of (x^3/(1-x)) is (3x^2-2x^3)/((1-x)^2)
What is the first derivative of (x^3/(1-x)) ?
The first derivative of (x^3/(1-x)) is (3x^2-2x^3)/((1-x)^2)