What is the derivative of x^3+2x^2+x-7 ?

The derivative of x^3+2x^2+x-7 is 3x^2+4x+1

What is the first derivative of x^3+2x^2+x-7 ?

The first derivative of x^3+2x^2+x-7 is 3x^2+4x+1

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\frac{d}{d x} (x^{3} + 2 x^{2} + x - 7)

3 x^{2} + 4 x + 1

Solution steps

\frac{d}{d x} (x^{3} + 2 x^{2} + x - 7)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) + \frac{d}{d x} (2 x^{2}) + \frac{d x}{d x} - \frac{d}{d x} (7)

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d x}{d x} = 1

\frac{d}{d x} (7) = 0

= 3 x^{2} + 4 x + 1 - 0

Simplify

= 3 x^{2} + 4 x + 1

\frac{d}{d θ} (- cos (θ))

\int \frac{6}{2 x - 5} d x

n = 0 \sum \infty \frac{0 ^{n}}{3 ^{n}}

\frac{\partial}{\partial z} (z arctan (\frac{y}{x}))

\frac{d}{d s} (s - t)

What is the derivative of x^3+2x^2+x-7 ?
The derivative of x^3+2x^2+x-7 is 3x^2+4x+1
What is the first derivative of x^3+2x^2+x-7 ?
The first derivative of x^3+2x^2+x-7 is 3x^2+4x+1