What is the solution for 49y^{''}-16y=0 ?

The solution for 49y^{''}-16y=0 is y=c_{1}e^{(4t)/7}+c_{2}e^{-(4t)/7}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

49y^{''}-16y=0

49 y^{^{''}} - 16 y = 0

y = c_{1} e^{\frac{4 t}{7}} + c_{2} e^{- \frac{4 t}{7}}

Solution steps

49 y^{''} (t) - 16 y = 0

Solve linear ODE:

y = c_{1} e^{\frac{4 t}{7}} + c_{2} e^{- \frac{4 t}{7}}

y = c_{1} e^{\frac{4 t}{7}} + c_{2} e^{- \frac{4 t}{7}}

\frac{3 ^{2}}{( s + 3 ) ^{2}}

\int 1 + cos (t) d t

y = 2 x^{3}, (- 1, - 2)

\int tan (y) d y

What is the solution for 49y^{''}-16y=0 ?
The solution for 49y^{''}-16y=0 is y=c_{1}e^{(4t)/7}+c_{2}e^{-(4t)/7}