What is the integral from 0 to infinity of 1/(x^3) ?

The integral from 0 to infinity of 1/(x^3) is diverges

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integral from 0 to infinity of 1/(x^3)

\int_{0}^{\infty} \frac{1}{x ^{3}} d x

diverges

Solution steps

\int_{0}^{\infty} \frac{1}{x ^{3}} d x

Compute the indefinite integral:

\int \frac{1}{x ^{3}} d x = - \frac{1}{2 x ^{2}} + C

Compute the boundaries:

\int_{0}^{\infty} \frac{1}{x ^{3}} d x =

diverges

= diverges

\int (x^{4} + 6 x^{2}) (4 x^{3} + 12 x) d x

\frac{d}{d x} (e^{x} (x - 2))

\frac{30}{x ^{7}}

x \to 0 + lim ((1 + x)^{\frac{3}{x}})

\frac{\partial}{\partial x} (e^{x} cos (x y))

What is the integral from 0 to infinity of 1/(x^3) ?
The integral from 0 to infinity of 1/(x^3) is diverges