What is the derivative of 3sin(2x+cos(2x)) ?

The derivative of 3sin(2x+cos(2x)) is 6cos(2x)-sin(2x)*2

What is the first derivative of 3sin(2x+cos(2x)) ?

The first derivative of 3sin(2x+cos(2x)) is 6cos(2x)-sin(2x)*2

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\frac{d}{d x} (3 sin (2 x) + cos (2 x))

6 cos (2 x) - sin (2 x) \cdot 2

Solution steps

\frac{d}{d x} (3 sin (2 x) + cos (2 x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 sin (2 x)) + \frac{d}{d x} (cos (2 x))

\frac{d}{d x} (3 sin (2 x)) = 6 cos (2 x)

\frac{d}{d x} (cos (2 x)) = - sin (2 x) \cdot 2

= 6 cos (2 x) - sin (2 x) \cdot 2

y = x (3 x + 2)^{5}

f (x) = \frac{8}{x ^{2} + x + 2}, at x = 2

t^{2} \frac{d y}{d t} + 4 t y - y^{3} = 0

h \to + 0 lim (2 x + h)

\frac{\partial}{\partial x} (ln (x^{3} + y^{5}))

What is the derivative of 3sin(2x+cos(2x)) ?
The derivative of 3sin(2x+cos(2x)) is 6cos(2x)-sin(2x)*2
What is the first derivative of 3sin(2x+cos(2x)) ?
The first derivative of 3sin(2x+cos(2x)) is 6cos(2x)-sin(2x)*2