What is the solution for 7x-4ysqrt(x^2+1)(dy)/(dx)=0,y(0)=6 ?

The solution for 7x-4ysqrt(x^2+1)(dy)/(dx)=0,y(0)=6 is y=sqrt((7\sqrt{x^2+1)+65)/2}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

7x-4ysqrt(x^2+1)(dy)/(dx)=0,y(0)=6

7 x - 4 y x^{2} + 1 \frac{d y}{d x} = 0, y (0) = 6

y = \frac{7 x ^{2} + 1 + 65}{2}

Solution steps

7 x - 4 y x^{2} + 1 \frac{d y}{d x} = 0

Solve separable ODE:

y = \frac{7 x ^{2} + 1 + 65}{2}

y = \frac{7 x ^{2} + 1 + 65}{2}

7 tan (x)

\frac{d}{d x} (e x^{2} - y)

\int x 1 - x d x

\int (x^{2} + 3)^{5} 2 x d x

\frac{\partial}{\partial x} (- \frac{x ^{2}}{y ^{2}})

What is the solution for 7x-4ysqrt(x^2+1)(dy)/(dx)=0,y(0)=6 ?
The solution for 7x-4ysqrt(x^2+1)(dy)/(dx)=0,y(0)=6 is y=sqrt((7\sqrt{x^2+1)+65)/2}