What is the first d/(dt)(te^t) ?

The first d/(dt)(te^t) is e^t+e^tt

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

d/(dt)(te^t)

\frac{d}{d t} (t e^{t})

e^{t} + e^{t} t

Solution steps

\frac{d}{d t} (t e^{t})

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = t, g = e^{t}

= \frac{d t}{d t} e^{t} + \frac{d}{d t} (e^{t}) t

\frac{d t}{d t} = 1

\frac{d}{d t} (e^{t}) = e^{t}

= 1 \cdot e^{t} + e^{t} t

Simplify

= e^{t} + e^{t} t

g (t) = \frac{3 t ^{2} - 1}{2 t + 5}

\int 33 arctan (x) d x

x \to 0 - lim (\frac{e ^{\frac{2}{x}} \cdot sin ( π ( x ) )}{x + 2} + x)

x \to 0 lim (\frac{8 sin ( 0 )}{0})

x + y = 3, y^{2} = 4 x, y = 0, 1