What is the integral of 2sqrt(z) ?

The integral of 2sqrt(z) is 4/3 z^{3/2}+C

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integral of 2sqrt(z)

\int 2 z d z

\frac{4}{3} z^{\frac{3}{2}} + C

Solution steps

\int 2 z d z

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int z d z

Apply the Power Rule

: \frac{2}{3} z^{\frac{3}{2}}

= 2 \cdot \frac{2}{3} z^{\frac{3}{2}}

Simplify

2 \cdot \frac{2}{3} z^{\frac{3}{2}} : \frac{4}{3} z^{\frac{3}{2}}

= \frac{4}{3} z^{\frac{3}{2}}

Add a constant to the solution

= \frac{4}{3} z^{\frac{3}{2}} + C

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