What is the derivative of x^3+2x-1 ?

The derivative of x^3+2x-1 is 3x^2+2

What is the first derivative of x^3+2x-1 ?

The first derivative of x^3+2x-1 is 3x^2+2

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derivative of

x^{3} + 2 x - 1

3 x^{2} + 2

Solution steps

\frac{d}{d x} (x^{3} + 2 x - 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) + \frac{d}{d x} (2 x) - \frac{d}{d x} (1)

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (2 x) = 2

\frac{d}{d x} (1) = 0

= 3 x^{2} + 2 - 0

Simplify

= 3 x^{2} + 2

F (x) = 7 x^{6} (x^{4} - 7 x)

\frac{d}{d x} (tan (3 x))

f (x) = 2 x^{2}, at x = 4

\int cos (π x) d x

\frac{\partial}{\partial y} (x^{3} - 3 x y^{2})

What is the derivative of x^3+2x-1 ?
The derivative of x^3+2x-1 is 3x^2+2
What is the first derivative of x^3+2x-1 ?
The first derivative of x^3+2x-1 is 3x^2+2