What is the derivative of f(x)=e^x\sqrt[3]{x} ?

The derivative of f(x)=e^x\sqrt[3]{x} is e^x\sqrt[3]{x}+(e^x)/(3x^{2/3)}

What is the first derivative of f(x)=e^x\sqrt[3]{x} ?

The first derivative of f(x)=e^x\sqrt[3]{x} is e^x\sqrt[3]{x}+(e^x)/(3x^{2/3)}

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Solution steps

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

\frac{d}{d x} (e^{x}) = e^{x}

\frac{1}{3 x ^{\frac{2}{3}}} e^{x} = \frac{e ^{x}}{3 x ^{\frac{2}{3}}}

y = x^{3} - 7 x^{2} + 8 x + 1

\int \frac{arctan ( e ^{x} )}{e ^{x}} d x

\int \frac{4}{4 - t ^{2}} d t

x \to 1 lim (\frac{x + 4}{1 + x ^{2}})

\int x x^{2} + 4 d x

What is the derivative of f(x)=e^x\sqrt[3]{x} ?
The derivative of f(x)=e^x\sqrt[3]{x} is e^x\sqrt[3]{x}+(e^x)/(3x^{2/3)}
What is the first derivative of f(x)=e^x\sqrt[3]{x} ?
The first derivative of f(x)=e^x\sqrt[3]{x} is e^x\sqrt[3]{x}+(e^x)/(3x^{2/3)}